Net Displacement with Pythagoras
Net Displacement और Pythagoras
Net Displacement with Pythagoras
- Direction Sense
- Net Displacement with Pythagoras
Find the shortest distance and final direction from the start by tracking net East-West and North-South movement.
🎯 Learning Objective
Find the shortest distance and final direction from the start by tracking net East-West and North-South movement.
💡 Concept
- Split every move into East-West (horizontal) and North-South (vertical)
- Add up: net East-West and net North-South separately (opposite moves cancel)
- Shortest (straight-line) distance = √(horizontal² + vertical²)
- Final direction is the corner between the two net directions (e.g. North + East = North-East)
- Watch for standard triples: 3-4-5, 5-12-13, 8-15-17 — they save calculation
🧮 Key Formulas
Shortest distance = √(net East-West² + net North-South²)
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Triples: 3-4-5, 5-12-13, 8-15-17
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Opposite moves cancel out
✏️ Easy Example
Q. Ravi walks 3 km towards the East, then 4 km towards the North. How far is he from the starting point?
- Net East = 3 km, net North = 4 km
- Distance = √(3² + 4²) = √(9 + 16) = √25
Answer: 5 km
🇮🇳 Real-Life Example
Walking blocks in a planned city like Chandigarh — 3 blocks across, 4 blocks up — the crow-flight distance home is this same right-triangle shortcut.
📝 Exam-Level Example
Q. Aman starts from home, walks 10 m North, turns East and walks 6 m, then turns South and walks 4 m. How far and in which direction is he from home?
- Net North-South: 10 North − 4 South = 6 North
- Net East-West: 6 East
- Distance = √(6² + 6²) = √72 = 6√2 ≈ 8.49 m; direction is North-East
Answer: 6√2 m (≈ 8.49 m), North-East
📝 Exam-Level Example
Q. A person walks 5 km towards the South, then 12 km towards the East. Find the shortest distance and direction from the start.
- Net South = 5 km, net East = 12 km
- Distance = √(5² + 12²) = √(25 + 144) = √169 = 13
- He is to the South and East of start → South-East
Answer: 13 km, South-East
📝 Exam-Level Example
Q. Rohan drives 8 km West, then 6 km North, then 8 km East. Where is he now relative to his start?
- Net East-West: 8 West − 8 East = 0 (they cancel)
- Net North-South: 6 North
- So he is simply 6 km due North of the start
Answer: 6 km towards the North
🪄 Memory Trick
Draw the path on a rough grid as you read — a quick sketch instantly shows which moves cancel and which corner the answer sits in.
⚠️ Common Mistakes
- ❌ Adding all distances instead of taking net (opposite directions must cancel)
- ❌ Forgetting to take the square root at the end
- ❌ Naming the direction backwards — state it from the START to the person
🏆 Exam Tips
- ✅ Memorise the 3 common triples so you skip long square-root work
- ✅ Keep East-West and North-South totals in two separate columns
📌 Summary
- Split moves into E-W and N-S, then net them
- Shortest distance = √(net horizontal² + net vertical²)
- Direction = corner of the two net directions
- Use triples 3-4-5, 5-12-13, 8-15-17 to save time