Painted Cube Cut into Smaller Cubes

Painted Cube को छोटे cubes में काटना

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Painted Cube Cut into Smaller Cubes

  • Dice & Cubes
  • Painted Cube Cut into Smaller Cubes
नमस्ते दोस्तों, कैसे हैं आप सब? चलिए आज की class शुरू करते हैं। आज का topic है — Painted Cube को छोटे cubes में काटना। मैं promise करती हूँ, आज के बाद ये topic आपको आसान लगेगा। शुरू करें?
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Learning Objective

Count how many small cubes have 3, 2, 1 or 0 painted faces when a painted cube is cut into n×n×n pieces.

🎯 Learning Objective

Count how many small cubes have 3, 2, 1 or 0 painted faces when a painted cube is cut into n×n×n pieces.

💡 Concept

  • Paint all 6 faces of a cube, then cut it into n×n×n = n³ equal small cubes
  • 3 painted faces = the CORNER cubes = always 8 (a cube has 8 corners)
  • 2 painted faces = the EDGE cubes (not corners) = 12 × (n − 2)
  • 1 painted face = the FACE-centre cubes = 6 × (n − 2)²
  • 0 painted faces = the hidden INNER cubes = (n − 2)³
  • Check: 8 + 12(n−2) + 6(n−2)² + (n−2)³ always equals n³

🧮 Key Formulas

3 faces painted = 8

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2 faces painted = 12 × (n − 2)

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1 face painted = 6 × (n − 2)²

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0 faces painted = (n − 2)³

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Total = n³

✏️ Easy Example

Q. A painted cube is cut into 27 equal small cubes (n = 3). How many small cubes have exactly 3 painted faces?

  1. 3 painted faces = the corner cubes
  2. A cube always has 8 corners

Answer: 8

🇮🇳 Real-Life Example

A 3×3×3 Rubik's cube is exactly this: 8 corner pieces show 3 colours, 12 edge pieces show 2, 6 centre pieces show 1, and 1 hidden core shows none.

📝 Exam-Level Example

Q. A painted cube is cut into 64 equal small cubes (n = 4). How many have exactly 2 painted faces?

  1. 2 painted faces = 12 × (n − 2)
  2. = 12 × (4 − 2) = 12 × 2

Answer: 24

📝 Exam-Level Example

Q. For the same cube cut into 64 pieces (n = 4), how many small cubes have NO face painted?

  1. 0 painted faces = (n − 2)³
  2. = (4 − 2)³ = 2³

Answer: 8

📝 Exam-Level Example

Q. A painted cube is cut into 125 equal small cubes (n = 5). How many have exactly 1 painted face?

  1. 1 painted face = 6 × (n − 2)²
  2. = 6 × (5 − 2)² = 6 × 9

Answer: 54

🪄 Memory Trick

Memorise the four counts by position: corners 8, edges 12(n−2), faces 6(n−2)², core (n−2)³. Every single one uses (n − 2), never n.

⚠️ Common Mistakes

  • ❌ Using n instead of (n − 2) in the edge, face and core formulas
  • ❌ Mixing up edges (2 faces) with face-centres (1 face)
  • ❌ Thinking corner cubes change with n — they are always 8

🏆 Exam Tips

  • ✅ Always write n first, then (n − 2), before plugging into the formulas
  • ✅ Sanity check: your four counts must add back up to n³

📌 Summary

  • 3 faces → 8 corners (fixed)
  • 2 faces → 12(n−2) edges
  • 1 face → 6(n−2)² face-centres
  • 0 faces → (n−2)³ core; all four sum to n³