Probability Basics — Coins, Dice, Cards
Probability की शुरुआत — सिक्का, dice, cards
Probability Basics — Coins, Dice, Cards
- Probability
- Probability Basics — Coins, Dice, Cards
Compute P = favourable/total for coins, dice and playing cards, and use P(not E) = 1 − P(E).
🎯 Learning Objective
Compute P = favourable/total for coins, dice and playing cards, and use P(not E) = 1 − P(E).
💡 Concept
- P(E) = favourable outcomes / total outcomes
- P lies between 0 (impossible) and 1 (certain); P(not E) = 1 − P(E)
- Coin: 2 outcomes; two coins: 4 outcomes; die: 6 outcomes
- Deck: 52 cards = 4 suits × 13; 26 red + 26 black; 12 face cards (J, Q, K of each suit)
- The formula works only when all outcomes are equally likely
🧮 Key Formulas
P(E) = favourable / total
>
0 ≤ P(E) ≤ 1
>
P(not E) = 1 − P(E)
✏️ Easy Example
Q. A die is thrown once. Find the probability of getting a number greater than 4.
- Favourable: 5, 6 → 2 outcomes
- Total = 6
- P = 2/6
Answer: 1/3
🇮🇳 Real-Life Example
The cricket toss is P = 1/2, and a weather app saying '80% chance of rain' is announcing probability 0.8 — you use this maths daily.
📝 Exam-Level Example
Q. One card is drawn from a well-shuffled deck of 52 cards. Find the probability that it is a king.
- Kings in deck = 4
- P = 4/52
Answer: 1/13
📝 Exam-Level Example
Q. A bag has 3 red and 5 blue balls. One ball is drawn at random. Find the probability that it is red.
- Total balls = 3 + 5 = 8
- Favourable = 3
Answer: 3/8
🪄 Memory Trick
'Not' questions: compute the easy side and subtract from 1. P(not a king) = 1 − 1/13 = 12/13 — no counting of 48 cards.
⚠️ Common Mistakes
- ❌ Counting outcomes that are not equally likely
- ❌ Getting P > 1 — impossible, recheck the total
- ❌ Counting the ace as a face card — face cards are only J, Q, K
🏆 Exam Tips
- ✅ Write total outcomes FIRST, then list favourable ones
- ✅ Memorise the deck: 4 × 13, 26 red, 26 black, 12 face cards
📌 Summary
- P = favourable/total, between 0 and 1
- Coin 2, two coins 4, die 6, deck 52
- 12 face cards; ace is not one
- P(not E) = 1 − P(E)