Quadratic Equations — Factorization & Roots

Quadratic Equations — Factorization और Roots

title

Quadratic Equations — Factorization & Roots

  • Algebra Basics
  • Quadratic Equations — Factorization & Roots
नमस्ते दोस्तों, कैसे हैं आप सब? चलिए आज की class शुरू करते हैं। आज हम सीखेंगे — Quadratic Equations — Factorization और Roots। घबराइए मत, हम एकदम basic से शुरू करेंगे। Ready? चलिए!
Scene 1/13
Learning Objective

Solve quadratics by factorization, use sum and product of roots, and apply the formula when factors are not obvious.

🎯 Learning Objective

Solve quadratics by factorization, use sum and product of roots, and apply the formula when factors are not obvious.

💡 Concept

  • A quadratic has the form ax² + bx + c = 0 (highest power 2), giving up to two roots.
  • Factorization: split the middle term b into two numbers that ADD to b and MULTIPLY to a·c.
  • For x² + bx + c, sum of roots = −b and product = c (when a = 1).
  • In general: sum of roots = −b/a and product of roots = c/a.
  • Quadratic formula: x = [−b ± √(b² − 4ac)] / (2a); the part b² − 4ac is the discriminant D.

🧮 Key Formulas

Sum of roots = −b/a, Product = c/a

>

x = [−b ± √(b² − 4ac)] / (2a)

>

Discriminant D = b² − 4ac

✏️ Easy Example

Q. Solve by factorization: x² − 5x + 6 = 0

  1. Find two numbers that add to −5 and multiply to 6: they are −2 and −3
  2. x² − 2x − 3x + 6 = 0 → (x − 2)(x − 3) = 0
  3. x − 2 = 0 or x − 3 = 0

Answer: x = 2 or x = 3

🇮🇳 Real-Life Example

Finding the side of a rectangular railway plot when its area and the difference of its sides are known leads straight to a quadratic — geometry and quadratics go hand in hand.

📝 Exam-Level Example

Q. Without solving, find the sum and product of the roots of x² − 8x + 15 = 0. Then name the roots.

  1. Here a = 1, b = −8, c = 15
  2. Sum of roots = −b/a = 8; Product = c/a = 15
  3. Two numbers with sum 8 and product 15 are 3 and 5

Answer: Sum = 8, Product = 15; roots are 3 and 5

📝 Exam-Level Example

Q. Solve using the quadratic formula: 2x² − 7x + 3 = 0

  1. a = 2, b = −7, c = 3; D = b² − 4ac = 49 − 24 = 25
  2. √D = 5, so x = (7 ± 5) / (2×2) = (7 ± 5)/4
  3. x = 12/4 = 3 or x = 2/4 = 1/2

Answer: x = 3 or x = 1/2

🪄 Memory Trick

For a = 1, quickly search two numbers that add to −b and multiply to c. If they exist, factorization beats the formula; if not, fall back on the formula.

⚠️ Common Mistakes

  • ❌ Using sum = +b/a instead of −b/a (the sign is negative)
  • ❌ Splitting the middle term with wrong signs so the product fails
  • ❌ Forgetting the ± in the formula and reporting only one root

🏆 Exam Tips

  • ✅ Check the discriminant: D > 0 real & distinct, D = 0 equal, D < 0 no real roots
  • ✅ Verify roots by substituting back or checking sum/product

📌 Summary

  • Form ax² + bx + c = 0, up to two roots
  • Factor by splitting the middle term (add to b, multiply to a·c)
  • Sum = −b/a, Product = c/a
  • Formula x = [−b ± √(b²−4ac)]/2a; D decides root nature